Problem 2 An LR circuit (with an Inductance of 6 mH and Resistance of 3 mΩ) is charging. How much time has passed when the current is ¾ of its maximum?
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Step 1: The current in an LR circuit charging is given by: $I(t) = I_{max}(1 - e^{-t/\tau})$ where: $I(t)$ is the current at time t $I_{max}$ is the maximum current $\tau = L/R$ is the time constant L is the inductance R is the resistance Show more…
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