00:01
Hello students, given the joint density function of x and y as c into e raised to minus 6x minus 8y where 0 less than y less than x.
00:09
In order to find the constant c, we can equate the joint density function to 1.
00:14
Therefore, c integral 0 to infinity e raised to minus 6x integral e raised to minus 8y is e raised to minus 8y divided by minus 8 from 0 to x dx is equal to 1.
00:29
Taking minus 8 outside minus c by 8 integral 0 to infinity e raised to minus 6x e raised to minus 8x minus 1 dx which is equal to 1 minus c by 8 integral 0 to infinity e raised to minus 14x minus e raised to minus 6x dx which is equal to 1.
00:53
Now let's take the integral of x which is minus c by 8 e raised to minus 14x divided by minus 14 minus e raised to minus 6x divided by minus 6 from the limit 0 to infinity which is equal to 1 minus c by 8 minus 1 by 14 into 0 minus 1 plus 1 by 6 into 0 minus 1 which is equal to 1 which is minus c by 8 1 by 14 minus 1 by 6 which is equal to 1.
01:32
Therefore, this is 8c divided by 672 which is equal to 1.
01:42
Therefore, the value of c is c is equal to 672 divided by 8 which is 84.
01:53
Therefore, f of x y is 84 e raised to minus 6x minus 8y 0 less than y less than x.
02:03
Now in a part of the question we want to find p of x less than 2 y less than 1 by 3...