00:01
So, we are given that for buck dc -dc converter supply voltage v is 50 volt, the constant k 0 .4, inductance l 400 microhenry, capacitance 100 microfarad, frequency 20 kilohertz, the resistance r 20 ohm, assuming an ideal components.
00:38
So, in a part we just calculate the output voltage.
00:42
So, since we know the concept that the output voltage for buck dc -dc converter is given by the supply voltage times of the conversion factor that is k.
00:57
So, this should be equals to supply voltage is 50 multiplied by k 0 .4 5 power 20.
01:03
So, once you get cancel the output voltage v 0 will comes out equals to 20 volt.
01:09
So, this is the answer for a part.
01:12
Now, let's have a look to b part.
01:14
So, in maximum condition the inductor current should be equals to the resistance current.
01:21
So, let us calculate first the inductor current i l this should be equals to the output voltage by inductive reactance or you can say the resistance because it's becoming equals to the resistive current.
01:35
So, this should be equals to the 20 volt divided by the resistance is 20 ohm will comes out equals to 1 ampere.
01:44
So, we just calculate the value of change in inductor current delta i l that can be given by the formula v 0 by l into the bracket 1 minus k times of t.
02:00
So, basically this t representing the time period which will be equals to 1 by f substituting this here we get v 0 is 20 volt divided by inductance is 400 micro henry that means 10 to the power minus 6 multiplied by 1 minus k 0 .4 times of t will be 1 over f, f is 20 kilohertz that means 20 into 10 to the power 3...