Question

Problem 2 You have two identical organ pipes with both ends open. You adjust the length of one pipe by making it 5 cm shorter and as a result hear a beat of 2 Hz from the interference of the fundamental frequencies of both pipes. You do this operation in dry air at 20 C, so you can assume the speed of sound is $v_{sound} =$ $343 \frac{m}{s}$. a) What was the original length of both pipes and the original fundamental frequency? b) You now close one end of the shortened pipe. What is the frequency of its third harmonic? How would you have to change the length of the open pipe to have a 3$^{rd}$ harmonic with the same frequency?

          Problem 2
You have two identical organ pipes with both ends open. You adjust the length of one pipe by making it 5
cm shorter and as a result hear a beat of 2 Hz from the interference of the fundamental frequencies of
both pipes. You do this operation in dry air at 20 C, so you can assume the speed of sound is $v_{sound} =$
$343 \frac{m}{s}$.
a) What was the original length of both pipes and the original fundamental frequency?
b) You now close one end of the shortened pipe. What is the frequency of its third harmonic? How
would you have to change the length of the open pipe to have a 3$^{rd}$ harmonic with the same
frequency?

Problem 2
You have two identical organ pipes with both ends open. You adjust the length of one pipe by making it 5
cm shorter and as a result hear a beat of 2 Hz from the interference of the fundamental frequencies of
both pipes. You do this operation in dry air at 20 C, so you can assume the speed of sound is vsound =
343 (m)/(s).
a) What was the original length of both pipes and the original fundamental frequency?
b) You now close one end of the shortened pipe. What is the frequency of its third harmonic? How
would you have to change the length of the open pipe to have a 3^rd harmonic with the same
frequency?

Added by Karen C.

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