00:01
In this problem, we're given four different spectra and we're asked to give a structure to match this.
00:10
So first we want to look at our formula here.
00:14
And we're going to find what's called degrees of unsaturation, also abbreviated as dou.
00:20
This will tell us how many pi bonds in a ring.
00:23
So we take two times the number of carbons and add two, subtract the number of hydrogens and divide by two.
00:31
We get two.
00:33
So we can have two rings, although with five carbons that's pretty unlikely, two pi bonds, or we could have one pi bond plus one ring.
00:47
And when we look at our ir, it's going to tell us about our pi bonds.
00:54
So notice that at 1738, we have a nice peak there.
01:01
That's for a carbonyl.
01:04
So then the only other pi bond we could possibly have would be between carbons.
01:09
Well, notice there's no other sharp peak there.
01:13
And there's no sp2 or sp carbon -hydrogen indications above 3000.
01:24
So we probably have a carbonyl and a ring...