Problem 23.59 The 10 ? resistor in (Figure 1) is dissipating...

Problem 23.59 The 10 ? resistor in (Figure 1) is dissipating 43 W of power. Figure 5.0 ? 10 ? 20 ? How much power is the 5.0 ? resistor dissipating? Express your answer to two significant figures and include the appropriate units. $P_{5.0}$ = Value Units Part B How much power is the 20 ? resistor dissipating? Express your answer to two significant figures and include the appropriate units. $P_{20}$ = Value Units

Transcript

00:01 First consider sub -path a.

00:03 The resistors of values 10 -oom and 20 -oom are connected in parallel.

00:11 The equivalent resistance of these two resistors connected in parallel is given by 1 by r p is equal to 1 by 10 ome plus 1 by 20 o or rp is equal to 1 by 1 by 10 om plus 1 by 20 om which gives the value of the equivalent resistance of the two resistors connected in parallel to be 6 .67 o.

00:46 The equivalent resistance of the total circuit or the equivalent resistance of the 5 oom resistance connected in series with the rp is given by r equivalent is equal to rp plus 5 .0 ome which gives the equivalent resistance of the circuit to be 6 .67 ome plus 5 .0 which gives the value of the equivalent resistance of the circuit to be 11 .67 the equation for the power is given by p is equal to i squared r here i is the current and r is the resistance.

01:39 The equation for the power dissipated across the 10 -on resistor is given by p 10 -oam is equal to i 10 -oom square into 10 om substituting the value of p -10 -oam gear 43 watt is equal to i 10m squared into 10 om or i 10 ome squared is equal to 43 watt divided by 10 om or the current across the 10 norm resistor is equal to root of 43 watt divided by 10 om which is equal to 2 .074 ampere.

02:35 The equation for the power is also given by b is equal to ib.

02:41 Here v is the voltage.

02:43 Rearranging this equation for the voltage gives v.

02:46 B is equal to p by i.

02:49 The equation for the voltage drop across the 10 -norm the sister is given by b -10 -0 is equal to p -10 -o divided by i10m substituting the values in the equation gives the 10m is equal to 43 watt divided by 2 .074 amp which is equal to 20 .736 watt the 10 -on resistor and the 20 -on resistor are connected in parallel the voltage across resistors connected in parallel will be identical therefore the voltage drop across the 20 -oom resistor is also equal to 20 .736 volt.

03:40 The equation for the power dissipated across the 20 -oom resistor is given by p -20 -oom is equal to v20 -oom squared divided by 20 -oom.

03:55 Substituting the values in the equation gives, p -20 -oom is equal to 20 -oom...

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