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Hello students, today we will discuss about this question.
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In this question we are given that alice and bob have two n plus one coins and each coin with probability of heads equals to 1 divide by 2.
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So here probability of head is equals to 1 divide by 2 and bob tosses n plus 1 coins while alice tosses.
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The remaining and coins.
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Now assuming the independent coin tosses show that the probability that after all coins have been tossed.
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So here we need to find the probability.
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We need to say that the probability, we need to prove that the probability of bob have gotten more heads than alice.
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Equals to 1 divide by 2.
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So here we need to prove this.
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So first of all let x that will be a number of heads of bob coin.
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So therefore we can say that x will follow a binomial distribution of n plus 1 to 1 divided by 2.
01:34
And here y that is equals to a number of heads of alleys...