00:01
So, let's solve the question.
00:03
For part a, we have 150 ml of 40 .1 percent of lithium nitrate that is lino3 solution.
00:27
Calculating, we get 100 ml to have 40 .1 gram.
00:37
Therefore, 1 ml will have 40 .1 divided by 100 grams.
00:44
That means, for the question asked, for 160 ml, so for 160 ml, we have 401 divided by 100 multiplied by 160.
00:56
Solving, we get the answer as 4 .01 multiplied by that is we have m equal to 64 .16 grams.
01:10
So, for two significant figures, we can say that m is equal to 64 of grams.
01:18
That means, this is the amount of mass present in the 160 ml of lithium nitrate...