Question

Problem 3. (1 point) Find an angle $\theta$ in the interval $\left[ -\frac{\pi}{2}, \frac{\pi}{2} \right]$ such that $\cot(\theta) = -\sqrt{3}$. Your answer must be in radians. Use "pi" for $\pi$ $\theta = -\frac{\text{pi}}{3}$

          Problem 3. (1 point)
Find an angle $\theta$ in the interval $\left[ -\frac{\pi}{2}, \frac{\pi}{2} \right]$ such that $\cot(\theta) = -\sqrt{3}$. Your answer must be in radians. Use "pi" for $\pi$
$\theta = -\frac{\text{pi}}{3}$

Problem 3. (1 point)
Find an angle θ in the interval [ -(π)/(2), (π)/(2)] such that cot(θ) = -√(3). Your answer must be in radians. Use "pi" for π
θ = -(pi)/(3)

Added by Austin S.

Precalculus with Limits

Ron Larson 2nd Edition

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Problem 3. (1 point) Find an angle heta in the interval -(pi )/(2),(pi )/(2) such that cot( heta )=-sqrt(3). Your answer must be in radians. Use "pi" for heta = Problem 3.(1point) TT TT Find an angle in the interva such that cot-3.Your answer must be in radians.Use"pi"for 2 2 0= -pi/3