00:01
In this question we have a given table to refer and now the value for m is 1000 frees for the and we will take here t of x which is given as 15 kgis and sample size is equal to 10 so now here for this question actual height or i'm sorry, weight, p .y is given above in the equation.
00:49
So we will find here our mean value for y -dash which will be equal to submission of all values of y divided by number of values.
00:57
So here we will get as the values are actual weight 14 plus 18 plus 16 plus 12 plus 12 plus 12 plus 24 plus 15 plus 15 plus 17 plus 17 plus 15 plus 17 plus 16 plus 18 divided by 10 so that is equal to 162 divided by 10 and will be equal to 11616 .2.
01:28
So here we have our value for y -dash and now let's find out our value for x dash.
01:34
Again this will be a summation of all values we are finding here mean so some of all observation divided by number of observation.
01:41
So when we find all the values sum as 12 plus 16 plus 19 plus 15 plus 11 plus 22 plus 13 plus 16 plus 14 plus 15.
01:58
So these are the values further divided by again 10 because number of observations are 10 and therefore x bar will be equal to 153 divided by 10.
02:11
So bar x is equal to 15 .3.
02:15
So now this is our value for mean of x and then hence our equation will be tiy is equal to 15 plus 1000 our regulation equation multiplied by 16 .2 minus 15 .3.
02:39
So our final value for tyy will be equal to 915...