Question

Problem 3 Consider the electric field at the boundary \textit{(xy} plane\textit{)} between two dielectric materials. Find $E_1$ if the boundary has a surface charge density of $\rho_s = 3.54 \cdot 10^{-11} \text{ C/m}^2$ and $E_2 = \hat{x}3 - \hat{y}2 + \hat{z}2 \text{ V/m}$, $\epsilon_1 = 2\epsilon_0$, $\epsilon_2 = 18\epsilon_0$.

          Problem 3
Consider the electric field at the boundary \textit{(xy} plane\textit{)} between two dielectric materials. Find $E_1$ if
the boundary has a surface charge density of $\rho_s = 3.54 \cdot 10^{-11} \text{ C/m}^2$ and
$E_2 = \hat{x}3 - \hat{y}2 + \hat{z}2 \text{ V/m}$, $\epsilon_1 = 2\epsilon_0$, $\epsilon_2 = 18\epsilon_0$.

Problem 3
Consider the electric field at the boundary (xy plane) between two dielectric materials. Find E1 if
the boundary has a surface charge density of = 3.54 · 10^-11 C/m^2 and
E2 = x̂3 - ŷ2 + ẑ2 V/m, ϵ1 = 2ϵ0, ϵ2 = 18ϵ0.

Added by Manuel I.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sufiyan Alam

Step 1

Since the electric field is given as E = x^3 - y^2 + z^2 V/m, we can see that the electric field is independent of the dielectric materials. Therefore, the electric field in each dielectric material will be the same. Show more…

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Problem 3: Consider the electric field at the boundary (xy plane) between two dielectric materials. Find E if the boundary has a surface charge density of Ïƒ = 3.54 Ã— 10^-11 C/m^2 and E = x^3 - y^2 + z^2 V/m, Îµ_0 = 2Îµ_0, Îµ_r = 18.