00:01
So here we have to determine the moment in the frame abcd which is shown here.
00:06
So this is a frame, this is point a, here is point b, here is point b and this is point c.
00:18
So we have to determine the momentum.
00:21
So here in this question this is basically the free body diagram.
00:25
This is given that is 3 kilo newton per meter, this is 5 centimeter, this is 3 meter, this is 2 meter, a force of 2, 3 kilo newton is acting that is 2 meter.
00:37
So we have to find out the fixed, now we are considering about the fixed end moments.
00:46
So here this is for the part 1, m dash of ab is equals to minus omega multiplied by the l square that is divided by 12.
00:56
So this from here is equals to 3 multiplied by the 5 to its whole square that is divided by 12.
01:01
So solving the term from here we get the value of m dash for ab that is equals to minus 6 .25 kilo newton meter.
01:09
So this is moment about the ab.
01:11
Now we are considering about the moment about ba that is equals to plus 6 .25 kilo newton meter.
01:18
Now we are considering about the moment across bc that is equals to minus rho l which is divided by 8 that is equals to minus 3 multiplied by the 4 which is divided by 8 that is equals to minus 1 .5 kilo newton and the momentum about the point cb is equals to plus 1 .5 kilo newton meter and the momentum about bd is equals to momentum about db that is equals to 0.
01:49
So therefore momentum about ab is equals to momentum about ab plus 2 of e i which is divided by l plus 2 of phi of a plus phi of b...