00:01
In this case, we have to give a relationship between these two molecules.
00:05
Now, if we look at these two molecules closely enough, this is the front carbon, let's say this is the carbon number a, that's the carbon number b in both of these cases, because these are two carbon atoms.
00:17
In front we have a hydroxyl group, a ch3nh, so we have oh, ch, the group, so the side chains on the carbon a are exactly the same.
00:27
On the b also we have a ch3 here, ch3 here we have bromine and hydrogen atom.
00:33
That means these two compounds, they have the same atoms.
00:39
Now the only thing that we have to look is for their arrangement.
00:42
That what is the arrangement of these side chains on these carbon atoms? because the relationship depends upon this arrangement in the 3d space, whether they will be an entomers or they will be diosteromers.
00:58
Now, if two compounds, they are stereosomer, that means they have the same atoms, but they only differ in their arrangement than they are known as stereosomers.
01:08
They could be of two types.
01:10
The first is an insumers, and they are formed when one is the mirror image of another.
01:16
If they are not mirror images of each other, then they are known as diastereomers.
01:22
In this case, if we look closely, this bond right here is a rotatable...