To find the value of k, we need to make sure that the probability density function (pdf) integrates to 1 over its domain. So, we have:
$$\int_{0}^{1} kx \, dx = 1$$
Now, we can solve for k:
$$k \int_{0}^{1} x \, dx = k \left[\frac{1}{2}x^2\right]_0^1 = k \cdot
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