Problem 3. The vapor phase decomposition of phosphine, which is irreversible and first order, follows the reaction:
4PH3(g) -> P4(g) + 6H2(g)
Pure phosphine is fed to a tubular-flow reactor, operating at 1 atm and adiabatically with a feed temperature of 953 K. The reaction is endothermic, ΔHR = 23,900 J/mol of phosphine at 25°C. The molar heat capacities (J/mol K) are
P4(g) Cp = 25.1 + 0.0040 T
PH3(g) Cp = 28.0 + 0.027 T
H2(g) Cp = 30.1
The rate constant k, (s)-1, is the following function of temperature:
ln k = 27.94 + 2 ln T - 43672/T , T (K)
What volume to initial molar feed rate ratio (V/FAo) would be required to obtain a conversion of 10% in one pass through the reactor? What would be the conversion for the same V/FAo if the reactor operated isothermally at 953 K?
Hint: From the energy balance get a quadratic expression on T, and use the positive solution to get an expression of T as a function of XA. Add this expression as an explicit equation to the ODE software.