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Problem 4. (20 points) Let A, B and C be 2 \times 2 matrices, such that $det(A) = -8$, $det(B) = 2$, and $det(C) = -3$. Find $det(D)$, where $D = 2B^3 A^{-1} C^T$.

          Problem 4. (20 points) Let A, B and C be 2 \times 2 matrices, such that $det(A) = -8$,
$det(B) = 2$, and $det(C) = -3$. Find $det(D)$, where $D = 2B^3 A^{-1} C^T$.

Problem 4. (20 points) Let A, B and C be 2 ×2 matrices, such that det(A) = -8,
det(B) = 2, and det(C) = -3. Find det(D), where D = 2B^3 A^-1 C^T.

Added by Timothy L.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Sri K

12/11/2022

Step 1

Step 1: Using the properties of determinants, we can write: det(D) = det(2B³A-1CT) = 22det(B)3det(A)-1det(C)T Show more…

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Problem 4. (20 points) Let A, B and C be 2 x 2 matrices, such that det(A) = -8, det(B) = 2, and det(C) = -3. Find det(D), where D = 2B³A-1CT.

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Problem 4. (20 points) Let A, B and C be 2 \times 2 matrices, such that $det(A) = -8$, $det(B) = 2$, and $det(C) = -3$. Find $det(D)$, where $D = 2B^3 A^{-1} C^T$.

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