Question

Problem 4: A rock is fired at ground level with an initial speed of 42 m/s, at an angle of 31° above the horizontal. It hits a target above the ground 2.2 seconds later. (a) What is the horizontal distance, in meters, from where the rock was fired to where it hits the target? (b) What is the vertical distance, in meters, from where the rock was fired to where it hits the target?

          Problem 4:   A rock is fired at
ground level with an initial speed of 42 m/s, at an angle
of 31° above the horizontal. It hits a target above the
ground 2.2 seconds later.
(a)  What is the horizontal distance,
in meters, from where the rock was fired to where it hits the
target? 
 (b)  What is the vertical
distance, in meters, from where the rock was fired to where it hits
the target?
        
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Added by Tanya R.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Problem 4: A rock is fired at ground level with an initial speed of 42 m/s, at an angle of 31° above the horizontal. It hits a target above the ground 2.2 seconds later. (a) What is the horizontal distance, in meters, from where the rock was fired to where it hits the target? (b) What is the vertical distance, in meters, from where the rock was fired to where it hits the target?
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Transcript

-
00:01 All right, so let's say a rock is fired at a 40, sorry, a 31 degree angle at 42 meters per second like this.
00:12 And we want to know if it hits a target 2 .2 seconds later.
00:19 So we'll call t this.
00:21 What is the horizontal distance in meters from where the rock is fired to the target? so we'll call us x.
00:26 This is going to be v cosine theta times t.
00:30 So 42 meters a second times the cosine of 31 times 2 .2 seconds.
00:42 And so this should be 79 .2 meters.
00:46 And then presumably for part b, we want to know what's the height of the projectile of the particle...
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