00:01
In this question, the young's modulus of steel is given as 200 giga pascal.
00:05
For the brass, it is given as 12 giga pascal.
00:09
Load is given as 50 kilo newton per meter and assume young's modulus is moment of inertia is 201 into 10 to the power 6 meter to the power 4.
00:23
The distance ab is given as 6 meter.
00:27
The vertical length is given as 5 meter.
00:30
Horizontal length is given as 13 meter and the length bc is given as 7 meter.
00:39
So, for beam 1, the reflection will be minus wa cube divided by 24 eil cube l multiplied by 4 l square minus 7 al plus 3 a square.
01:00
So, the calculation leads us to del b1 as minus 204 .94 into 10 raised to the power minus 3 meter.
01:12
Now, for beam 2, the deflection will be given by minus p b by ab divided by 6 eil multiplied by l square minus a square minus b square...