Since the block is accelerating, the force exerted by the cable (F_cable) is equal to the mass of block A (m) times the acceleration of point P (a_P), which is given by:
\[ F_{cable} = m \cdot a_P \]
\[ F_{cable} = 75 \, \text{kg} \cdot 6 \, \text{m/s}^2 \]
\[
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