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Problem 5. Find the domain of each function using the interval notation. \begin{align*} (a) \ f(x) &= \frac{\sqrt{x-4}}{\sqrt{x-6}} \\ (b) \ f(x) &= \frac{x^2 - 9x}{x^2 - 81} \end{align*}

          Problem 5. Find the domain of each function using the interval notation.
\begin{align*}
(a) \ f(x) &= \frac{\sqrt{x-4}}{\sqrt{x-6}} \\
(b) \ f(x) &= \frac{x^2 - 9x}{x^2 - 81}
\end{align*}
        
Problem 5. Find the domain of each function using the interval notation.

    (a)  f(x)    = (√(x-4))/(√(x-6))
    
    (b)  f(x)    = (x^2 - 9x)/(x^2 - 81)

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Problem 5. Find the domain of each function using the interval notation. (a) f(x)=(sqrt(x-4))/(sqrt(x-6)) (b) f(x)=(x^(2)-9x)/(x^(2)-81) Problem 5. Find the domain of each function using the interval notation (a) f(x) =Vx-4 Vx-6 (b)f= 2-81
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Transcript

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00:01 In this question, f of x is equal to arc co -secant of x plus 5.
00:08 And we want to find what our domain is.
00:10 What can we plug in here? well, this quantity, x plus 5, needs to be less than are equal to negative 1, or it needs to be greater than x plus 5.
00:22 Raise that simple...
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