00:01
In this question, we will solve first for the a part.
00:04
It is given that the fluid density is equal to rho is equal to 1000 and we have to compute the inlet mass flow rate per unit depth of the channel, that is the depth of the channel in z direction.
00:17
We will write y is equal to 1 divided by x, x lies between 1 to 2.
00:25
Width of the channel is equal to 1 unit.
00:32
The cross section area of the channel at distance x is a is equal to y minus w.
00:48
Here a is equal to 1 divided by x at x is equal to 1.
00:54
A is equal to flow is steady and uniform to mass flow.
00:59
Therefore, the mass flow to 2, it has constant.
01:05
So we can write p1, p1 is equal to da2v2.
01:11
So, a1v1 is equal to a2v2.
01:18
So we can write it as 1 multiplied by 2 is divided by x multiplied by 2 is equal to 2 multiplied by n.
01:35
At n is equal to 2, vu minus 1 is equal to 2 is equal to 4...