In this case, θ = 1, so we have e^j = cos(1) + j*sin(1).
b) To compute e^-j, we can use the fact that e^-j = 1/e^j. Using the result from part a), we have e^-j = 1/(cos(1) + j*sin(1)).
To express the answers in polar form, we need to convert the complex numbers
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