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Problem 6: (10% of Assignment Value) Consider a 0.85 kg aluminum pot containing 2.65 kg of water. Substances Specific heat (c) Solids J/kg°C kcal/kg °C Aluminum 900 0.215 Concrete 840 0.20 Copper 387 0.0924 Glass 840 0.20 Human Body (37°C) 3500 0.83 Iron, steel 452 0.108 Liquids Water 4186 1.000 Mercury 139 0.0333 theexpertta.com Part (a) How much heat, in kilocalories, must be transferred to raise the temperature of the aluminum pot and the water from 30.0°C to the boiling point of water and then boil away 0.775 kg of water (Lv = 539 kcal/kg)? Q= sin() cos() tan() π 789 HOME cotan() asin() acos() E 4 6 atan() acotan() sinh() 123 cosh() tanh() cotanh() 0 END Degrees Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! 999 Submission(s) Remaining Feedback: 0% deduction per feedback. Hints: 0% deduction per hint. Hints remaining: 1 Part (b) How long, in seconds, does this take if the rate of heat transfer is 500 W? Grade Summary Deductions 0% Potential 100% Submissions Attempt(s) Remaining: 999 0% Deduction per Attempt detailed view Activate Windows Go to Settings to activate Wine

          Problem 6: (10% of Assignment Value)
Consider a 0.85 kg aluminum pot containing 2.65 kg of water.
Substances
Specific heat (c)
Solids
J/kg°C
kcal/kg °C
Aluminum
900
0.215
Concrete
840
0.20
Copper
387
0.0924
Glass
840
0.20
Human Body (37°C)
3500
0.83
Iron, steel
452
0.108
Liquids
Water
4186
1.000
Mercury
139
0.0333
theexpertta.com
Part (a)
How much heat, in kilocalories, must be transferred to raise the temperature of the aluminum pot and the water from 30.0°C to the boiling point of water and then
boil away 0.775 kg of water (Lv = 539 kcal/kg)?
Q=
sin()
cos()
tan()
π
789
HOME
cotan()
asin() acos()
E
4
6
atan()
acotan()
sinh()
123
cosh()
tanh() cotanh()
0
END
Degrees Radians
VO BACKSPACE
DEL CLEAR
Submit
Hint
Feedback
I give up!
999 Submission(s) Remaining
Feedback: 0% deduction per feedback.
Hints: 0% deduction per hint. Hints remaining: 1
Part (b)
How long, in seconds, does this take if the rate of heat transfer is 500 W?
Grade Summary
Deductions
0%
Potential
100%
Submissions
Attempt(s) Remaining: 999
0% Deduction per Attempt
detailed view
Activate Windows
Go to Settings to activate Wine

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problem 6 10 of assignment value consider a 085 kg aluminum pot containing 265 kg of water substances specific heat c solids jkgc kcalkg c aluminum 900 0215 concrete 840 020 copper 387 00924 46477

Added by Adam G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Suman K

08/12/2022

Step 1

0°C to 100°C is given by: $$Q_1 = m_A c_A \Delta T$$ where: * $m_A$ is the mass of the aluminum pot (0.85 kg) * $c_A$ is the specific heat of aluminum (0.215 kcal/kg °C) * $\Delta T$ is the change in temperature (100°C - 30.0°C = 70.0°C) Substituting the values, we Show more…

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Problem 6: (10% of Assignment Value) Consider a 0.85 kg aluminum pot containing 2.65 kg of water. Substances Specific heat (c) Solids J/kg°C kcal/kg °C Aluminum 900 0.215 Concrete 840 0.20 Copper 387 0.0924 Glass 840 0.20 Human Body (37°C) 3500 0.83 Iron, steel 452 0.108 Liquids Water 4186 1.000 Mercury 139 0.0333 theexpertta.com Part (a) How much heat, in kilocalories, must be transferred to raise the temperature of the aluminum pot and the water from 30.0°C to the boiling point of water and then boil away 0.775 kg of water (Lv = 539 kcal/kg)? Q= sin() cos() tan() π 789 HOME cotan() asin() acos() E 4 6 atan() acotan() sinh() 123 cosh() tanh() cotanh() 0 END Degrees Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! 999 Submission(s) Remaining Feedback: 0% deduction per feedback. Hints: 0% deduction per hint. Hints remaining: 1 Part (b) How long, in seconds, does this take if the rate of heat transfer is 500 W? Grade Summary Deductions 0% Potential 100% Submissions Attempt(s) Remaining: 999 0% Deduction per Attempt detailed view Activate Windows Go to Settings to activate Wine

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00:01 Hello students in this question we are given an aluminum pot so the mass of the aluminum pot is equals to 0 .95 kg which contains water so the mass of the water is equals to 3kj and the temperature is initially equals to 30 degrees celsius and the final temperature is 100 degrees celsius which is a boiling point and we have to boil away mass of the water which has to be boiled away is 0 .8 kg so we have to calculate the amount of heat transfer which is required in part a so the amount of heat transfer will be equal to so we have to first rise the temperature of the aluminum which will be mass of aluminum multiplied by the specific heat cap.

01:05 Of aluminum multiplied by the change in temperature plus mass of water multiplied by the specific heat capacity of water multiplied by the change in temperature plus the mass of water which we have to boil away is multiplied by l which is a latent heat of vaporization so it will be equals to 0 .95 multiplied with the specific heat capacity of aluminium which is 0 .215 kilo calorie so we will multiply by 10 to the power 3 multiplied with the change in temperature is 70 plus mass of the water which is 3 multiplied by the specific heat capacity of water which is 1 kilo calorie so it will be 1 multiplied by 10 to the power 3 multiplied by change in the temperature is 70 plus mass of the water which has to be boiled away is 0 .8 multiplied by the spousalant heat of vaporization which is 539 multiplied by 10 to the power 3 so it will come out equals to 6 it will be 6 55.

02:30 0 .4975 kilo calorie now in the b part we are given that the rate of heat transfer is rate of heat transfer is 500 watt which is equal to 500 joules per second so we have to calculate the time for this heat transfer so the time will be equals to the total heat which is 6554 .4975 multiplied by 10 to the 3 for converting calorie into juice it will be multiplied with 4 .1 over 500 so it will come out equals to so it will basically come out in seconds we will convert it into minutes it will come out to be 91 .33 minutes so now let us write our answer our answer to the question is for the part a is 655 .497 kilo calorie and for the b part it is 91 .33 minutes...

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