00:01
Hi, in this question we have been given a free body diagram.
00:07
So here we have this diagram over which we have a force acting on this edge which is fc and for angle this is given as 3, 4 and 5.
00:25
So with the help of this we can find the inclination of this force and then at the center we have 500 newton of load and then we have at this point 500 newton load.
00:41
In the horizontal direction here this is ax, this is the reaction and in the vertical direction this is ay.
00:51
So this distance is of 2 meter and this distance is 1 meter and this distance is also 1 meter.
01:01
Now we need to find the shear force and bending moment diagram for the given loading condition.
01:09
So we will find the moment about point a and this should be equal to 0 for the equilibrium condition.
01:20
So this is point a, this is point b and this is point c.
01:24
So we can write fc multiplied by 3 divided by 5 that is this vertical component of force.
01:38
So this will be fc times 3 divided by 5 and there will be a horizontal component of force as well and this will be fc 4 divided by 5.
01:50
So here fc times 3 divided by 5 multiplied by distance is 4 and then minus 500 multiplied by 2 and then minus 500 times 1 and this would be equal to 0.
02:05
So here for the sign convention, clockwise movement we are taking negative and anticlockwise we are taking positive.
02:17
So from here we will get 12 fc divided by 5 equal to 1500.
02:25
So fc will be equal to 625 newton.
02:31
Now we will write summation of forces acting in y direction that is equal to 0.
02:38
So this will be equal to ay plus 625 multiplied by 3 divided by 5 minus 500 minus 500 and this would be equal to 0.
02:51
So from here again we will get ay is also equal to 625 newton.
02:55
So now we will draw the shear force diagram.
03:03
So at x equal to 0 that is shear force at x location and this will be equal to ay and this is given as 625 newton.
03:15
Then at x equal to 2 this shear force will be equal to 625 minus 500 and this will be equal to 125 newton.
03:31
So this is just before 500 newton load and then at x equal to 2 as the x will be equal to 625 minus 500 and then minus 500 newton which is equal to minus 375 newton.
03:50
It is just after x equal to 2 meter...