Problem 89. A particular good eye has a distance from the effective lens to the retina of 2.25 cm. This eye has a nearpoint of 12 cm. A) What is the effective focal length of this eye when relaxed. B) What is the smallest possible focal length of this eye?
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Given: v = 2.25 cm u = 12 cm Plugging in these values into the formula, we get: 1/f = 1/2.25 - 1/12 Simplifying this equation, we get: 1/f = (12 - 2.25) / (2.25 * 12) 1/f = 9.75 / 27 1/f = 0.3611 Show more…
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