Question

(8%) Problem 9: A block with mass $m_1$ = 8.5 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of $mu_k$ = 0.55. A second block with a mass $m_2$ = 8.9 kg is connected to the first by an ideal pulley system such that the second block is hanging vertically. The second block is released and motion occurs. 20% Part (a) Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, $Sigma F_y$, for block 2. $Sigma F_y = T - m_2g$ Correct! 20% Part (b) Using the variable T to represent tension, write an expression for the sum of the forces in the x direction, $Sigma F_x$ for block 1. $Sigma F_x = T - mu_k m_1 g$ Correct! 20% Part (c) Write an expression for the magnitude of the acceleration of block 2, $a_2$, in terms of the acceleration of block 1, $a_1$. (Assume the cable connecting the masses is ideal.) $a_2 = a_1$ Correct! 20% Part (d) Write an expression using the variables provided for the magnitude of the tension force, T.

          (8%) Problem 9: A block with mass $m_1$ = 8.5 kg rests on the surface of a horizontal
table which has a coefficient of kinetic friction of $mu_k$ = 0.55. A second block with a mass
$m_2$ = 8.9 kg is connected to the first by an ideal pulley system such that the second block is
hanging vertically. The second block is released and motion occurs.
20% Part (a) Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, $Sigma F_y$, for block 2.
$Sigma F_y = T - m_2g$ Correct!
20% Part (b) Using the variable T to represent tension, write an expression for the sum of the forces in the x direction, $Sigma F_x$ for block 1.
$Sigma F_x = T - mu_k m_1 g$ Correct!
20% Part (c) Write an expression for the magnitude of the acceleration of block 2, $a_2$, in terms of the acceleration of block 1, $a_1$. (Assume the
cable connecting the masses is ideal.)
$a_2 = a_1$ Correct!
20% Part (d) Write an expression using the variables provided for the magnitude of the tension force, T.

(8%) Problem 9: A block with mass $m1$ = 8.5 kg rests on the surface of a horizontal
table which has a coefficient of kinetic friction of muk = 0.55. A second block with a mass
m2 = 8.9 kg is connected to the first by an ideal pulley system such that the second block is
hanging vertically. The second block is released and motion occurs.
20% Part (a) Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, $Sigma Fy$, for block 2.
Sigma Fy = T - m2g Correct!
20% Part (b) Using the variable T to represent tension, write an expression for the sum of the forces in the x direction, $Sigma Fx$ for block 1.
Sigma Fx = T - muk m1 g Correct!
20% Part (c) Write an expression for the magnitude of the acceleration of block 2, $a2$, in terms of the acceleration of block 1, $a1$. (Assume the
cable connecting the masses is ideal.)
a2 = a1 Correct!
20% Part (d) Write an expression using the variables provided for the magnitude of the tension force, T.

Added by William K.

Question

Please give Ace some feedback