00:01
So in this question we have a baseball that is moving and then it hit a brick on a small roller.
00:11
Afterwards, the baseball bounces back and the brick moves forward.
00:18
So i'll call the ball a and then the break b.
00:21
We are asked to find what is the baseball speed after the collision.
00:26
And since we already know in the a, va, mb initial at rest so vb then we also know vb and because of that we should be able to find v a prime through the conservation of momentum so we have m a va is the initial speed the initial momentum the brick initial has no momentum because it was at rest afterwards we have an ava prime plus mb vb prime so we can see find m .a through v -a -p -a -prime through m -a -v -a -v -a minus m -b -b -b -p -p.
01:15
Hosing divided by m -a.
01:22
So, we have 0 .144 kilogram times 28 .0 meters per second minus 5 .25 kilogram times 1 .10 meters per second.
01:42
And divided by 0 .144 kilogram.
01:47
This is negative 12 .10 meters per second.
01:52
So this is the speed of the baseball after the collision.
01:56
We can see it's negative, so as the question says, it bounces straight back.
02:03
So the other thing we need to find is the total kinetic energy before and after the collision...