Problem: A kilometer of wire having a diameter of 11.7 mm and a resistance of 0.031 ohm is drawn down so that its diameter is 5.0 mm. What does its resistance become?
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Step 1
This relationship is given by the formula: R = ĻL/A where R is the resistance, Ļ is the resistivity (a property of the material), L is the length, and A is the cross-sectional area. In this problem, the length of the wire remains constant (1 km), but the Show moreā¦
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