Question

Problem I: a) For the circuit shown in Figure 1, both diodes are identical. Find the value of R for which VD2 - VD1 = 40 mV (Hint: iD = IS [ e^(vD/VT) - 1]) b) Given that IS = 10^-14 A, find the values of VD1 and VD2.

          Problem I:
a) For the circuit shown in Figure 1, both diodes are identical. Find the value of R for which VD2 - VD1 = 40 mV (Hint: iD = IS [ e^(vD/VT) - 1])
b) Given that IS = 10^-14 A, find the values of VD1 and VD2.
        

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Problem I: a) For the circuit shown in Figure 1, both diodes are identical. Find the value of R for which VD2 - VD1 = 40 mV (Hint: iD = IS [ e^(vD/VT) - 1]) b) Given that IS = 10^-14 A, find the values of VD1 and VD2.
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Transcript

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00:01 In the first question, the value of the voltage v is given which is 40 millivolt.
00:06 Then we have to find the value of the resistance are.
00:11 As we know that, both the diodes are identical with each other.
00:16 Then the current i passing through the d1 will be 5mphar and the current passing through the d2 is also similar which is 5 millie ampere so voltage v is given which is equal to 40 milliwalt and the current passing through the diode d1 is 5mmpire we have to find the resistance so here we will apply according to the ome slow the r can be given by v divided by i so this will be 40 millivolt divided by 5 mllie this will be cancelled out here we will get 8 so the value of the resistance r is equal to 8 om now in the second question the we have to to find the vd1 and voltage across the d1 and d2 diode where the value of the current i is given i as saturated current 10 to minus 14 ampere...
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