Problem 7
In atmospheric atmosphere (Pº = 1 bar), oxygenated water is separated in a free piston sealed container at 293 K temperature. The constant of the decomposition reaction is K = 2.10¹⁸.
a) Give the decomposition reaction.
b) What is the vapor pressure? The triple point of the water has values of 0,01°C and 611 Pa and the critical point has values of 374°C and 22 MPa. Considering the melting and boiling points of the water, which of the following pressures can be the vapor pressure at 20°C? Why?
a) 588 Pa b) 23,4 mbar c) 1,74 atm
c) Initially, 10 mL of water is added into the dry container with a piston level of 30 mL at 20°C. The piston level increased to around 40 mL and reached equilibrium.
Assuming that the gases behave ideally, calculate the vapor pressure of the gases under the piston.
d) Calculate the new air volume achieved by adding water into the container. Give the rate of change based on the initial volume of the new volume.
e) Calculate that the amount of water added is sufficient for the amount of evaporated water by calculating the rate of evaporation.
f) 10 mL oxygenated water with a concentration of 1 mol.L⁻¹ is added into the dry container with a piston level of 30 mL at 20°C. How the system is expected to develop over time by evaluating the decomposition constant of oxygenated water.
g) Before adding oxygenated water, calculate the amount of air, O₂ and N₂ in the dry container.
h) Then calculate the amount of O₂ formed as a result of decomposition, the final total volume (the amount of evaporated water is neglected).
j) In the final case, calculate the partial pressures of P₂ and P₂ under the piston.
k) The concentration of oxygenated water as a result of the decomposition reaction was followed in time as follows.
t (hour) 0 0,5 1,0 2,0 4,0 6,0
[H₂O₂] (mol.L⁻¹) 1,000 0,794 0,629 0,396 0,156 0,062
Calculate the degree of dissociation reaction and its kinetic constant k₂₉₃ by plotting.
m) Since the activation energy of the reaction is 75 kJ.mol-1, what is the kinetic constant k₃₀₀ value at 300 K temperature?
Data: R = 8.314 J.mol⁻¹.K⁻¹
Air = 0.8 N₂ + 0.2O₂ Mwater= 18 g.mol⁻¹
1 atm = 1 bar
ρwater = 1 g.cm⁻³