00:01
Hello guys, let's get started with the solution.
00:05
We are given the ksp values of pbs, pbso4, and pbi3 hold twice at 8 .4 into 10 -dusti -power minus 28.
00:28
And for the next one, it is 1 .8 into 10 -rest -power minus 8.
00:34
And for the next one it is 2 .6 into 10 x to power minus 301 now we know that ksp stands for solubility product therefore more ksp value means greater solubility hence we can say that lead sulfate among the three is most soluble while for lead iodide it is minus 13 rather than 31 and lead sulfide is the least soluble one now if we have to find the molarity of most soluble compound then for this part of the question we'll make use of ksp as pb 2 plus as so forth to minus ksp is 1 .8 times 10 to power minus 8 assuming the molarity as s equals to s so as here be 1 .8 times 10 this to power minus 8 therefore s equals a square root of 1 .8 times 10 to power minus 8 molar or equals 1 .34 times 10 to power minus 4 molar.
02:43
So this is the molarity of the most soluble compound.
02:55
Now if we have to find the molecular weight of the most soluble compound.
02:59
Now if we have to find the molecular weight of the most soluble compound, then we know that the compound is pbso4, where lead, that is pb is 207, sulfur is 32, and oxygen is 4 times 16...