Problem 8: The diagram shows the two forces with magnitudes...

Problem 8: The diagram shows the two forces with magnitudes F1 and F2 acting on a body. The first force is in the positive x direction, while the second makes an angle ? with the negative x direction, as shown. Part (a) Write an expression for the x component of the net force. ?Fx = F1 - F2 cos(?) Part (b) Write an expression for the y component of the net force. ?Fy = - F2 sin(?) Part (c) If the magnitudes are related by F1 = 2.59F2, and ? = 40.9 degrees, then what is the angle ? that the acceleration vector makes with the x axis, in degrees? ? = 340.31

Transcript

00:01 Hi there, so for this problem we have the situation that is shown in here.

00:06 For part a and par b, you already answer the question correctly.

00:12 So what we are given for par c of this problem is the magnitude of the force f1.

00:20 In this case, that will be 2 .59.

00:26 And the magnitude of the force 2, which is...

00:30 Oh, sorry, what we are given is that...

00:32 This force, the force f1, is 2 .59 times the force f2, and the angle theta, we are also given that angle, that is 40 .9 degrees.

00:48 So with that, then the question is, what is the angle b that the acceleration vector mates with the x axis? so what we need to do first is to obtain the s, and the white component of the net force, okay? so for that, we use the equations that we've taken from before.

01:09 That will be that the x component of the net force is equal to the force f1, and this minus the force f2 times the cosine of the angle.

01:19 So in this case, that will be the force f1.

01:24 So that will be, let me leave it, let me use this definition that we are given, 2 .59 times the force f2 and this minus the force f2 times the cosine of 40 .9 degrees.

01:42 Okay.

01:43 Then using our calculator, we obtain a value of.

01:53 So we're obtaining here that this is 1 .83 times the force f2.

01:59 So this is the x component of the net force.

02:02 Okay.

02:02 So for the white component of the net force, we just use that that is minus the force f2 times the sign of the angle.

02:13 Okay? so that will be then in this case, minus the force f2 times the sign of 40 .9 degrees...

Question

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