Problem1 An Open Belt Running over two pulleys 240mm and 600mm diameter connects two parallel shafts 3m apart. The power to be transmitted is 4 kW from the smaller pulley that rotates at 300rpm. Coefficient of friction between belt and pulley is 0.3 and the safe working tension is 10N per mm width. Determine: Minimum Width of belt (ans:178mm) Initial belt tension (ans: 1249.5N) Length of the belt required (ans:7.36m)
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Substituting the given values, we get v = π*0.24*300/60 = 3.77 m/s. Show more…
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An open belt running over two pulleys, one with a diameter of 240 mm and the other with a diameter of 600 mm, connects two parallel shafts that are 3 meters apart. The belt transmits 4 kW of power from the smaller pulley, which rotates at 300 r.p.m. Given that the coefficient of friction between the belt and the pulley is 0.3, determine the tension in both sides of the belt, the initial belt tension, and the length of the belt required.
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A flat belt, 8 mm thick and 100 mm wide transmits power between two pulleys, running at 1600 m/min. The mass of the belt is 0.9 kg/m length. The angle of lap in the smaller pulley is 165° and the coefficient of friction between the belt and pulleys is 0.3. If the maximum permissible stress in the belt is 2 MN/m2, find (i) Maximum power transmitted, and (ii) Initial tension in the belt. [Ans. 14.821 kW; 1.322 kN]
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