00:01
As for the question, the question is divided into two steps, step one and step two.
00:09
Step one is to crack size in the last cycle point prior of failure.
00:16
So af equals to ykc 2 by 1.
00:28
Hence kc is where kc equals to fracture toughness of steel, fracture toughness of steel.
00:49
Y equals to geometric factor, geometric factor and there is given alternating stress range, is alternating stress range.
01:19
So the substitute is, substitute is 54 mnm minus 3 by 2 for kc, for kc and 180 mnm minus 2 for v and 1 .12 for y.
02:00
So af is, af equals to 1 .12 into 18054251 equals to 0 .022838 m.
02:20
This is step one and the step second is, step second is number of cycles to failure from paris law.
02:32
Paris law is given, paris law is given.
02:42
What is paris law? n, f equals to a y naught pi root over, root over m 1 minus 2m plus 1 a minus 2m plus 1 ao af.
03:16
This is paris law and then, then where, where aa, a and m, a and m are constants for the dependent on material and natural for the test.
03:38
They are constants and depend on, depend on material, material and nature of the test and nature of the test and a is, small a is size of crack, size of crack and y is geometric factor, geometric factor and lambda is alternating stress range, alternating stress range, stress range.
04:42
So, compare the crack growth equation, dn da equals to ak3...