Problem 3. (25 points) The spring has an unstretched length of 0.4 m and a stiffness, k, of 200 N/m. The 3 kg slider and attached spring are released from rest at A and move in the vertical plane along the smooth rod. Using the work-energy or conservation of energy method, a) Calculate the speed of the slider as it reaches B. b) Calculate the magnitude and direction of the normal force of the rod on the slider at B.
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The spring is stretched by 0.2 m (0.6 m - 0.4 m) at point A. So, the initial potential energy of the spring is (1/2)kx^2 = (1/2)*200*(0.2)^2 = 4 J. The initial kinetic energy of the slider is zero because it is released from rest. The initial gravitational Show more…
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Question 3: The 4 kg-slider at point A is released from rest and slides down the vertical-plane guide. If the maximum compression of the spring is observed to be 40 mm, determine the work Uf done by the friction. a) Determine the kinetic energy of the slider at level 1 (T1) and at level 2 (T2) b) Determine the gravitational potential energy of the slider (Vg) c) Determine the potential energy of the spring (Ve) d) By writing the work and the energy equation between level 1 and level 2, determine the work done by the friction (Uf=?)
Frank D.
Kratika B.
In the given figure, the natural length of spring is $0.4 \mathrm{~m}$ and spring constant is $200 \mathrm{~N} / \mathrm{m}$. The $3 \mathrm{~kg}$ slider and attached spring are released from rest at end move in the vertical plane. The slider comes in rest at the point $B$. The work done by the friction during motion of slider is:(a) $-3.52 \mathrm{~J}$ (b) $-0.8 \mathrm{~J}$ (c) $-100 \mathrm{~J}$ (d) - 10.54 J
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