00:01
Here in this question we are given the speed n is given which is equal to 200 rpm.
00:09
Power is given which is equal to 75 kilowatts.
00:16
We have the value of modulus of rigidity which is 102 gigapascal and here the length l is equal to 2 meter.
00:28
Here the maximum permissible twist is given which is equal to 1 degree or this is equal to pi by 180 radian.
00:44
So this turns out to be 0 .01745 radian.
00:52
Now here first we need to calculate the speed of shaft.
00:57
Speed of shaft omega is equal to 2 into pi into the rotational speed n divided by 60.
01:05
So this turns out to be 2 pi the value of n is 200 rpm divided by 60.
01:10
Upon solving this we will get the value of omega to be 20 .943 radian per second.
01:21
Next we need to calculate the torque transmitted by the shaft is to be calculated.
01:27
The torque transmitted by the shaft is given by torque is equal to the power p divided by the speed.
01:44
So this is equal to the value of power is 75 kilowatt that is 75 into 10 power 3 watts divided by the speed is 20 .943 radian per second.
01:59
Upon solving this we will get the value of torque to be 3580 .986 newton meter.
02:10
Now by equation we know that torque t divided by polar moment of inertia j is equal to the modulus of rigidity g multiplied by the angle of twist theta divided by the length of shaft l is equal to the value of maximum shear stress tau divided by the radius r...