00:01
In this problem, we're looking at a compound that has a molecular formula of c7, h14 ,02.
00:12
And here, we're told that in ir, at 1740 inverse centimeters, we have an absorption.
00:22
This corresponds to carbonyl, so that's a carbon -oxygen double bond.
00:26
And if we look at our proton nmr data then, at 1 .2, we have a singlet, and this integrates to nine hydrogens.
00:52
At 1 .3, we have a triplet, and this corresponds to three hydrogens.
01:05
And this is going to represent two hydrogens.
01:11
So the first thing to note is we have this triplet and this quartet...