00:01
Hello students, consider the reaction ch3, ch2 nh2 plus h2o is ch3 -ch2 nx3 plus plus oh minus.
00:11
Pkb4 ch3 -ch2 is given as 3 .25.
00:16
There has to find out the ph when the concentration of ch3, ch2, nh3 plus divided by concentration of ch3, ch2, nh2 is equal to 10.
00:31
We know the equation p -o -h is equal to p -kb plus loque concentration of salt divided by concentration of paste.
00:54
This we can write as boh is equal to p kb plus loque concentration of ch3, ch2, nh3 plus divided by concentration of ch3, ch3, ch2, ch2, h2, nh2.
01:35
Now let's substitute the values.
01:39
This is equal to 3 .25 plus loque 10.
01:48
This we will get as 4 .25...