Question

A proton in a particle accelerator has a speed of 5.0 x 10^6 m/s. The proton encounters a magnetic field due whose magnitude is 0.40T and whose direction makes an angle of theta = 30° with respect to the proton's velocity as shown in figure below. Find the magnitude and direction of the magnetic force on the proton. v B 30° Select one: a. 2.20 x 10^-13 N, out of the page b. 1.60 x 10^-13 N, into the page c. 1.60 x 10^-19 N, out of the page d. 2.20 x 10^-19 N, into the page

          A proton in a particle accelerator has a speed of 5.0 x 10^6 m/s. The proton encounters a magnetic field due whose magnitude is 0.40T and whose direction makes an angle of theta = 30° with respect to the proton's velocity as shown in figure below. Find the magnitude and direction of the magnetic force on the proton. v B 30° Select one: a. 2.20 x 10^-13 N, out of the page b. 1.60 x 10^-13 N, into the page c. 1.60 x 10^-19 N, out of the page d. 2.20 x 10^-19 N, into the page

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A proton in a particle accelerator has a speed of 5.0 x 10^6 m/s. The proton encounters a magnetic field due whose magnitude is 0.40T and whose direction makes an angle of theta = 30° with respect to the proton's velocity as shown in figure below. Find the magnitude and direction of the magnetic force on the proton. v B 30° Select one: a. 2.20 x 10^-13 N, out of the page b. 1.60 x 10^-13 N, into the page c. 1.60 x 10^-19 N, out of the page d. 2.20 x 10^-19 N, into the page

Added by Andrew G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Christian Dell

04/24/2022

Step 1

6 \times 10^{-19} \) C Speed of proton, v = \( 5.0 \times 10^6 \) m/s Magnitude of magnetic field, B = 0.40 T Angle, \( \theta = 30^\circ \) Plugging in the values: \( F = (1.6 \times 10^{-19} \, C) \times (5.0 \times 10^6 \, m/s) \times (0.40 \, T) \times Show more…

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A proton in a particle accelerator has a speed of 5.0 x 10^6 m/s. The proton encounters a magnetic field due whose magnitude is 0.40T and whose direction makes an angle of theta = 30 degrees with respect to the proton's velocity as shown in figure below. Find the magnitude and direction of the magnetic force on the proton. Select one: a. 2.20 x 10^-13 N, out of the page b. 1.60 x 10^-13 N, into the page c. 1.60 x 10^-19 N, out of the page d. 2.20 x 10^-19 N, into the page

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