proton is released from rest at the positive plate of parallel plate capacitor the electric fiel

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Question

A proton is released from rest at the positive plate of a parallel plate capacitor. The electric field strength between the plates is 6.00 x 10^5 V/m. The proton exits from a small hole in the negative plate and enters a region of uniform magnetic field pointing out of the page. The proton moves in a circular orbit with a radius of 8.00 mm in the magnetic field. Uniform out of page 4.75 mm. What is the potential difference across the capacitor plates? How fast is the proton moving when it exits through the negative plate? In which direction (CW or CCW) does the proton circle in the magnetic field? What is the magnetic field strength? (If you are unable to complete part b, use a speed of 4.00 x 10^5 m/s for this part.)

          A proton is released from rest at the positive plate of a parallel plate capacitor. The electric field strength between the plates is 6.00 x 10^5 V/m. The proton exits from a small hole in the negative plate and enters a region of uniform magnetic field pointing out of the page. The proton moves in a circular orbit with a radius of 8.00 mm in the magnetic field. Uniform out of page 4.75 mm.
What is the potential difference across the capacitor plates? How fast is the proton moving when it exits through the negative plate? In which direction (CW or CCW) does the proton circle in the magnetic field? What is the magnetic field strength? (If you are unable to complete part b, use a speed of 4.00 x 10^5 m/s for this part.)

proton is released from rest at the positive plate of parallel plate capacitor the electric field strength between the plates is 600 x 10 vlm the proton exits from small hole in the negativ 66512

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