proton moves in a uniform magnetic field of strength 0.500 T magnetic field is directed along the x-axis. At initial time, t = 0 s, the proton has velocity
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500 T - Direction of the magnetic field: along the x-axis - Initial time (t) = 0 s - Proton's initial velocity (v) needs to be specified Show more…
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Lorentz Force A proton moves in a uniform magnetic field of strength 0.500 T. The magnetic field is directed along the X-axis. At the initial time, t=0s, the proton has a velocity of 1.95x10^45i+2.00x10^5k m/s. Find: What is the acceleration of the proton at t=3 mins?
Krishna S.
A proton moves through a uniform electric field given by $\mathbf{E}=50.0 \hat{\mathbf{j}} \mathrm{V} / \mathrm{m}$ and a uniform magnetic field $\mathbf{B}=$ $(0.200 \hat{\mathbf{i}}+0.300 \hat{\mathbf{j}}+0.400 \hat{\mathbf{k}})$ T. Determine the acceleration of the proton when it has a velocity $\mathbf{v}=200 \hat{\mathbf{i}} \mathrm{m} / \mathrm{s}$
A proton moves through a uniform electric field $\mathbf{E}=50.0 \mathbf{j} \mathrm{V} / \mathrm{m}$ and a uniform magnetic field $\mathbf{B}=$ $(0.200 \mathbf{i}+0.300 \mathbf{j}+0.400 \mathbf{k}) \mathrm{T}$. Determine the acceleration of the proton when it has a velocity $\mathbf{v}=200 \mathbf{i} \mathrm{m} / \mathrm{s}$.
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