00:01
Given in the question here, the force acting on a, which is 450 lb, is also 900 neutals.
00:12
And we are asked to calculate the force along the component ac.
00:16
First, we know that if your force x acts along a component which is inclined at an angle theta to x sizes, then there will be two components, the vertical and the horizontal, that the horizontal component will be x plus theta and the vertical component will be x sine theta now first taking the forces along the x axis the sum of forces along x axis is equal to zero then we have f a b sine theta which is we have theta is equal to 45 degrees so taking 45 degrees in place of teta plus fac, sound 75 degrees is equal to 0.
01:06
So we are asked to find this, that is the course along the component ac.
01:11
Now we have the force along the component av is equal to negative ac, sine 75 degrees, divided by 5, sine 45 degrees.
01:27
Now next, resolving the forces in the horizontal and vertical directions...