00:01
Hello students, hope you are doing great.
00:03
In this question we are given a reaction scheme where in the first step f molecule is synthesized, in the second step g molecule is synthesized and in the last step we have p molecule here.
00:14
So we have to find out what is f, g and p in this particular reaction scheme.
00:20
So let us start solving the question.
00:22
So here we have c6h5ch2br reacting with c6h5 thrice bonded with phosphorus.
00:37
We know that phosphorus is having the lone pair of electrons so it will attack on this carbon and the br bromide ion will leave from here.
00:46
After this we have the product like this.
00:48
Here we have c6h5ch2 bonded with phosphorus and phosphorus bonded with 3 moles of c6h5.
00:59
Now this is the f molecule.
01:08
After this, this molecule reacts with c6h5 lithium.
01:13
So lithium is having a positive charge and this phenyl group is having a negative charge.
01:19
So this negatively charged group will take a proton from here and there will be negative charge on this carbon.
01:28
So the product we have here is c6h5ch, negative charge on this carbon, phosphorus c6h5 thrice...