00:02
Hello students, hope you are doing great.
00:04
In this question, we are given an organic reaction and we are asked to find out the product for this reaction.
00:09
So here in the first step, this molecule that is given here reacts with acid.
00:13
So the lone pair of the lone pair that are present in oxygen will accept proton over here and here we have an intermediate something like this.
00:24
Here we have ch3, c double bond o, o, here we have hydrogen and here we have ch2ch3.
00:32
So this oxygen here is having a positive charge.
00:34
Now in the next step, this will react with methanol.
00:39
So the lone pair that are present on the oxygen of methanol will attack on this carbonyl carbon.
00:45
This bond will break from here and this oxygen gets the lone pair of electrons of this bond so that the positive charge of the oxygen is stabilized.
00:55
So here we have the final product that is this.
01:01
Here we have ch3 carbonyl carbon and here we have och3.
01:06
So this is our final product.
01:12
The next reaction that we have here is a reaction between carbonyl carbon and amine.
01:23
So the carbonyl carbon compound that we have here is something like this.
01:26
Here we have a six -membered ring which is having a carbonyl carbon over here and it is fused with a five -membered ring like this and here it reacts with amine.
01:36
So here we have ch3ch3, here we have hydrogen and here there are the lone pair of electrons.
01:41
So this pi electrons will attack on this carbon.
01:44
These electrons will move to the oxygen and oxygen gets the negative charge.
01:49
So the intermediate that is formed here is something like this.
01:52
The five -membered ring is fused like this.
01:55
Here we have o-, here we have nitrogen ch3ch3, here we have hydrogen and nitrogen having a positive charge...