Question

1) Provide the mechanism of the reaction below, catalyzed by triethylamine. The reaction should take you three mechanistic steps. (3 points) : NEt$_3$ H OH 2) Referring to the C=O group that already exists in the starting molecule: a) If this ketone were not present (for example, if it were just an H there instead), would the first step be faster or slower? Briefly explain. (3 points) b) If this ketone were not present (for example, if it were just an H there instead), would the second step be faster or slower? 3) If 9.21 g of the starting reactant is used and 0.27 g of triethylamine are used, approximately how many reactions will each molecule of triethylamine catalyze?

          1) Provide the mechanism of the reaction below,
catalyzed by triethylamine.
The reaction should take you three mechanistic steps. (3
points)
: NEt$_3$
H
OH
2) Referring to the C=O group that already exists in the
starting molecule:
a) If this ketone were not present (for example, if it were
just an H there instead), would the first step be faster or
slower? Briefly explain. (3 points)
b) If this ketone were not present (for example, if it were
just an H there instead), would the second step be faster
or slower?
3) If 9.21 g of the starting reactant is used and 0.27 g of
triethylamine are used, approximately how many
reactions will each molecule of triethylamine
catalyze?

1) Provide the mechanism of the reaction below,
catalyzed by triethylamine.
The reaction should take you three mechanistic steps. (3
points)
: NEt3
H
OH
2) Referring to the C=O group that already exists in the
starting molecule:
a) If this ketone were not present (for example, if it were
just an H there instead), would the first step be faster or
slower? Briefly explain. (3 points)
b) If this ketone were not present (for example, if it were
just an H there instead), would the second step be faster
or slower?
3) If 9.21 g of the starting reactant is used and 0.27 g of
triethylamine are used, approximately how many
reactions will each molecule of triethylamine
catalyze?

Added by Jared C.

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