Question

\psi(k) = \frac{1}{\sqrt{2\pi\hbar}} \int_{-\infty}^{\infty} e^{-\frac{ax^2}{2}} e^{-\frac{ikx}{\hbar}} dx

Name: ψ(k) = (1)/(√(2πħ)) ∫-∞^∞ e^-(ax^2)/(2) e^-(ikx)/(ħ) dx
Uploaded: 2023-05-30T18:34:24-08:00
Duration: 2 min 44 s
Channel: Adi S
Description: ψ(k) = (1)/(√(2πħ)) ∫-∞^∞ e^-(ax^2)/(2) e^-(ikx)/(ħ) dx

          \psi(k) = \frac{1}{\sqrt{2\pi\hbar}} \int_{-\infty}^{\infty} e^{-\frac{ax^2}{2}} e^{-\frac{ikx}{\hbar}} dx

Added by Michael L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

05/30/2023

Step 1

Step 1: Rewrite the given integral in a more simplified form: \psi(k) = \frac{1}{\sqrt{2\pi \hbar}} \int_{-\infty}^{\infty} e^{-\frac{ax^2}{2}} e^{-\frac{ikx}{\hbar}} dx Show more…

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