00:01
Hello students in this question they have given that at the name the view of the sun from the solar form is observed by the thick cloud.
00:16
The drops of 300 300 watt per meter square and the diffute irradiation is 150 watt per meter square.
00:32
So by using this graph we need to find what is the total? irradiation, that is irradiance on your panels.
00:46
So in the panel, what is the total irradiation with respect to, i mean in the units, w per meter square.
00:57
So we need to find this.
00:59
And they have also given that the tilt angle is 40 degree.
01:12
So by these values, we need to find what is the irradience.
01:16
The time is at the 10 a .m.
01:21
We need to remember that.
01:23
From the graph, from this graph, we can write that solar gentle angle, that is theta 5, is equals to 48 degree.
01:38
And solar azumuth angle alpha is equals to 140 degree.
01:44
These are the readings from the graph.
01:47
And also, the tilt angle they have given is 40.
01:50
Panel azumath angle that is si 6 is equals to 120 degree sorry 180 degree this is as if the face south the panel is faces at the south direction irradiation is given by i d1 is equals to i dn1 into so, sine theta, sine theta s, this is not phi, this is yes, sine theta s, sine beta, cos of si s minus alpha, plus cos theta s, cost beta...