2. (6 pts) A refrigerator has a coefficient of performance of 1.15, and it extracts 7.95 J of heat from the cold reservoir during each cycle. (a) How much work is done on the gas in each cycle? (b) How much heat is exhausted into the hot reservoir in each cycle?
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Given: Coefficient of performance (COP) = 1.15, Heat extracted from the cold reservoir (Q2) = 7.95 J We know that COP = Q2 / W, where W is the work done on the gas. Therefore, W = Q2 / COP W = 7.95 / 1.15 W = 6.913 J Show more…
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