A pulley consists of two concentric disks of radii R2 = 0.400 m and R1 = 3R2 that are welded together. The disks are equipped with a smooth, horizontal axle through their centres of mass, as shown. The moment of inertia of the pulley about the axle is 40 kg·m². Thin strings are wound around both disks and blocks of mass m1 and m2 are suspended as shown. (a) If m1 = 10 kg, find m2 such that the angular acceleration of the pulley is zero. For parts (b) and (c), assume that m1 = 36 kg and m2 = 72 kg. The moment of inertia of the pulley is still 40 kg·m². The pulley-blocks system is released from rest. (b) For these values of the masses, the system is no longer in static equilibrium. Let a1 be the magnitude of acceleration of m1 and a2 that of m2. Write down the kinematical relation between a1 and a2. (c) Use the second law (ΣF = ma and Στ = Iα) to determine the acceleration a1 of m1 and the tension T1 in the string attached to m1. (If instead you use conservation of energy (or, work-energy theorem), you’ll still be eligible for full credit.)