00:01
Hey there.
00:02
This is a freezing point depression problem.
00:05
So we need the equation that is used to calculate change in freezing point.
00:11
So that is delta tf, the change in freezing point, is equal to kf, which is the freezing point depression constant, which is based upon the solvent, times the molarity, or molality rather, little m, molality of the solution, multiplied by the vantahaf factor i.
00:33
The vantav factor is the number of particles the solute breaks into or dissociates into when it's in solution.
00:40
Well, the solution we're using here is a non -electrolite.
00:45
So that means it does not break into more particles than just itself.
00:51
So i is just going to be one.
00:53
So i am just going to erase i here because the vantaf factor is just one, so it's not going to change our equation.
01:01
Okay, so this is our equation.
01:04
And let's see what information we know.
01:07
We know that the normal freezing point for this is 6 .53.
01:16
So this solvent has a normal freezing point of 6 .53 degrees celsius.
01:37
The new freezing point we are told is 0 .78 degrees celsius.
01:44
So the difference will give us the change in freezing point.
01:48
In other words, that is 5 .75 degrees celsius, and that is our delta t .f.
01:57
That is how much the freezing point changed.
02:01
We also are given the kf.
02:03
We are told that kf is 20 .0 degrees celsius per molal.
02:11
Okay, so we can now solve for molality.
02:14
So let's go ahead and do that.
02:16
5 .75 degrees celsius is our.
02:22
Delta tf that is equal to 20 .0 degrees celsius per molaf times the molality.
02:31
Solving for molality we'll divide both sides by that 20 .0.
02:43
That way that will isolate the molality by itself.
02:46
Degrees celsius will cancel leaving molality as our unit.
02:52
So the the molality ends up being 0 .2875, and molality is moles of solute per kilogram of solvent...